The general formula of (1)C 1 is (X-4) 2+(Y-5) 2 = 25,

X 2+Y 2-8x- 10y+ 16 = 0，

Let x = ρcosθ, y=ρsinθ, and substitute it to get ρ 2-8 ρ cos θ-10 ρ sin θ+16 = 0.

(2) Method 1: Substitute ρ=2sinθ into the above formula to get-16 (sin θ) 2-16 sin θ cos θ+16 = 0.

The solution is θ = π/2 or π/4, ρ = 2 or √2,

Therefore, the polar coordinates of the intersection point are (2, π/2) or (√2, π/4).

Method 2: C2 equation is x 2+y 2 = 2y,

Combined with the equation of C 1, the coordinates of the intersection point are (0,2) or (1, 1).

The polar coordinates are (2, π/2) or (√2, π/4).