Find a solution to the above problems! ! ! Junior one math! !

Solution 1: Because P is the intersection of the center lines, that is, the center of gravity.

So Pb = 2pe, 2pd=ap.

And because the area of triangle ape is equal to sine value of angle ape of 1/2*ap*pe* = sine value of angle ape of PD * PE *.

The area of the triangle bpd is equal to the sine value of the angle bpd of 1/2*bp*pd* = the sine value of the angle bpd of PE * PD *.

Another small reason is that angle bpd= = angle ape, so the sine value of angle bpe is equal to the sine value of angle ape.

So the area of triangle ape is equal to the area of triangle bpd.

Solution 2: Connect cp.

So s △ ape = s △ EPC. ，s △ BDP = s △ PDC。

s△apc=2s△ape

Because,

s△apc:s△pdc=ap:pd=2: 1

So s△apc=2s△pdc

So1/2s △ APC = s △ ape = s △ PDC = s △ BDP.