Solution: a =? 1b=? 2c=3,
∴y=-x2-2x+3;
(2)y=-x2-2x+3=-(x+ 1)2+4,
∴P(- 1,4),
∴PA=25,PC=2,AC=32,
∫PA2 = PC2+AC2
∴∠PCA=90,
∴tan∠pac=pcac=232= 13;
(3) The analytical formula of linear AC is: y=x+3,
The analytical formula of linear AP is y=2x+6,
The analytical formula of linear PC is: y=-x+3,
When AC is the diagonal of parallelogram:
PC∨AM,AP∨CM,
∴ Using two parallel lines with equal values of k, we can get:
The analytical formula of the straight line MC is y=2x+3,
The analytical formula of linear AM is y=-x-3,
∴M(-2,- 1),
When PC is the diagonal of a parallelogram, ∴ m (2 2,7) can be obtained in the same way.
When AP is the diagonal of a parallelogram: ∴ m (-4, 1),
∴M(-2,-1) or m (2,7) or m (-4, 1).