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Compulsory math problem 1
1,f(0+ 1)= f(0)+f( 1)+2 * 1 * 0

Solve f(0)=0

f(0- 1)= f(0)+f(- 1)+2 *- 1 * 0

Solve f(- 1)=0.

f(- 1+(- 1))= f(- 1)+f(- 1)+2 *- 1 *- 1

Solve f(-2)=2

f(-2+(- 1))= f(-2)+f(- 1)+2 *-2 *- 1

Solve f(-3)=6

2,f(x)*f(x+2)= 13

f(x+2)*f(x+4)= 13

f(x)=f(x+4)

F(x) is a periodic function with a period of 4.

f(99)= f(4 * 24+3)= f(3)= 13/f( 1)= 6.5

3, let f (x) = kx+b.

2f(x)+f(-x)=3x+ 1

2kx+2b-kx+b=3x+ 1

kx+3b=3x+ 1

(k-3)x+3b- 1=0

For any x constant, it has nothing to do with the coefficient before x.

k=3 b= 1/3

y=3x+ 1/3

4. When x+2≥0 x≥-2, f(x+2)= 1.

x+(x+2)*f(x+2)=x+x+2f(9a-9)

F(x) is the increasing function defined within (0, positive infinity).

List the following inequalities

a>0

9a-9>0

A > 9a-9

Merge 1 < a < 9/8

6. First, make sure that m- 1 2m- 1 is within the definition domain.

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