A, reduced to the original B, expanded ten times C, unchanged.
(2) solution ratio
(2+X):2=2 1:6
6(2+X =42)
X=5
(3)
The actual distance is 350km and the scale is 1: 7000000. Find the distance on the map.
X:350= 1:7000000
X=0.00005 (km) = 5cm
The distance on the map is 6 cm, and the scale is 1: 5000000. Find the actual distance.
6:X= 1:5000000
X=30000000 (cm) =300 km.