1) The actual distance is fixed, the scale is expanded tenfold, and the distance on the map is (b).

A, reduced to the original B, expanded ten times C, unchanged.

(2) solution ratio

(2+X):2=2 1:6

6(2+X =42)

X=5

(3)

The actual distance is 350km and the scale is 1: 7000000. Find the distance on the map.

X:350= 1:7000000

X=0.00005 (km) = 5cm

The distance on the map is 6 cm, and the scale is 1: 5000000. Find the actual distance.

6:X= 1:5000000

X=30000000 (cm) =300 km.