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Mathematics competition of grade three
Assuming that there are X people who correctly answer A, Y people who correctly answer B and Z people who correctly answer C, then

x+y=45

x+z=35

y+z=40

There were 20 people who answered A correctly, 25 people who answered B and 15 people who answered C.

The total score is 20*20+25*40+ 15*40=2000.

Because three people answered three correctly, and 14 people answered two correctly, the total number of people x+y+z must be three right and two right, so x+y+z=60 people minus multiple calculations (three correctly counted twice and two correctly counted once).

Get 60-2*3- 14=40 people.

Average score =2000/40=50.

Oh, I haven't done the problem for a long time