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Fractional mathematics problem
1. Solve the equation

7x = 6, 3 = 3, 28?

Solution x = 28/3/7/6

x=8

X ÷ 2/5 = 2/5?

Solution x = 2/5 ÷ 2/5

x= 1

8x = two thirds

Solution x = 2/3 ÷ 8

The 12 part of X= 1

2. The seeder sows 5 hectares in 3/4 hours. How many hectares does this seeder sow 1 hour? How many hours does this seeder need to sow 1 hectare?

Solution of this seeder 1 hour sowing: 5/2 ÷ 3/4 = 10 (hectare)

The seeder needs to sow 1 hectare:1.3/10 = 65438+3/00 (hour).

3.( 1) A rope is 2/5 meters long and needs a quarter of its 1. How many meters did it take?

The solution of 5 1 = 1 00 1 2×4(m)

(2) A rope used 1 m, and there are 2 meters left. How long is this rope?

Solution 2/5+65438/4+0 = 65438/20+03 (m)

(3) A rope uses 1, which is exactly 2/5 meters. How long is this rope?

Solution 2/5/4 1 = 8/5 (m)

Is this question wrong? If it is "just 2/5 meters left", the solution will be different for your reference.

Remaining: 1-4 1 = 3/4.

2/5/3/4 = 65438+8/05

4. Calculation (writing process)

5÷ 12 of 6, 5 = 6, and 5×5 12 = 2?

65438+5 ÷ 20 = 65438+5×20 = 1 = 1=48?

4/3 12 1 65438+8/05.

= 4× 12× 8× 15.

= 16× 8 15

=30

9' s 8× 18÷5' s 4

= 8×65438+9 08× 5/4.

= 16× 5/4

=20

5.8 kilograms of cotton thread. 8 kg of children's socks 27. Adult socks No.27 per pair 12kg. How many pairs of children's socks can this box of cotton thread knit? How many pairs of adult socks can you knit?

Children's knitted socks: 8/3 ÷ 8/27 = 9 (deputy)

Woven adult socks: 8/3 ÷ 27/ 12=6 (pair)

6. A canal was dug in a village, which has been dug for 2/5 of the total length, just 1200m. What is the total length of this canal?

Solution 1200 ÷ 2/5 = 3000 (m)

7. On the left side of the balance is a 3/8 biscuit, and on the right side is a weight of 1 kg, which is just balanced. How much does the whole pie weigh

0 (kg) of 3 = 65438+3 of solution 1÷8.