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Mid-term exam of senior two mathematics last semester.
There are only 1 cases of female students in A- Chinese.

There are three situations after boys' generation B excludes Chinese and mathematics.

The remaining six people take three courses, that is, C6-3 has 6*5*4/( 1*2*3)=20.

Then * * * has 1*3*20=60 possibilities.

I don't understand the topic very well. Are both conditions met or do you choose a result under each condition?