So f (a) = e a+2a, and f (b) = EB+2B;
From A, we can know that: f (a) = f (b)+b; That is f (a)-f (b) = b >; 0;
So f(a)>f(b); So choose a.
Let g (x) = e x-2x,? g? (x)= e x-2 in x & gt; The sign of 0 is uncertain, so D and C can't judge right or wrong.