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Math problem ~ ~ February 2008 191000th day?
2008 is a leap year, so it exists on February 29th, 2008.

Therefore, the interval days from February 19 to February 2008 +0 1.02. 19 are:

365*3+ 1 = 1096

Add the date of February 19, 2008, and it is 1097 days.

Then 97 days before 2011.02.19 is the required date.

2011.02.19 ~ 2010.12.31every 50 days.

2010.12.31~ 2010.1day.

2010.11.30 ~ 2010.1.1416 days.

1097-(50+3 1+ 16)= 1000

Therefore, the1000th day from February 19, 2008 is 2010.1.14.