Then P(A)=2/3 and P(B)=3/4.
1、P( 1)=( 1-2/3)( 1-3/4)= 1/ 12
2, including A once, B missed.
A hit twice, but B missed.
Twice in a and once in b.
p(2)= 2/3 *( 1-2/3)*( 1-3/4)*( 1-3/4)+2/3 * 2/3 *( 1-3/4)*( 1-3/4)+2/3 *(2/3 *( 1-3/4)*( 1-3/4)+2/3 * 2/4
= 1/8