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A mathematical probability problem in college entrance examination
Answer: Remember that Event A is a pitching hit and Event B is a pitching hit.

Then P(A)=2/3 and P(B)=3/4.

1、P( 1)=( 1-2/3)( 1-3/4)= 1/ 12

2, including A once, B missed.

A hit twice, but B missed.

Twice in a and once in b.

p(2)= 2/3 *( 1-2/3)*( 1-3/4)*( 1-3/4)+2/3 * 2/3 *( 1-3/4)*( 1-3/4)+2/3 *(2/3 *( 1-3/4)*( 1-3/4)+2/3 * 2/4

= 1/8