w=x？ Y+x+3y, w=y(x? +3)+X. Where x and y are integers.

Option A says that if W is even, then X must be even. But x can be 0, odd or even. In this case, y only needs to be an even number.

Option b says that if x is odd, then w must be odd. X is an odd number, which will lead to y(x? +3) is even or 0, plus odd x equals odd.

The c option says that if y is odd, then w must be odd. It is also correct to replace x with 0, odd number and even number.

The D option says that if W is odd, then Y must be odd. But x is odd, y is even and w is odd.