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Creating Excellence in Mathematics in Grade One (Solving with Binary Linear Equation)
The second question is relatively simple. I'll write it to you first.

Suppose the distance from the school to A is X kilometers, and the walking distance of the seventh grade team is Y kilometers. Let's establish the equation.

x + y = 2 1

x/60+2 1/60 = 10/60+y/4

Solution, x = 19, y = 2.

The first question: A collocation price is 2*2+4* 1.2=8.8 yuan. Similarly, B matches 25.6 yuan, and C matches 2 1.2 yuan.

Suppose B sells X and C sells Y, then A sells (58-3X-2Y)/2, and the equation is listed.

8.8 *(58-3X-2Y)/2+25.6 x+2 1.2Y = 44 1.2

Simplification: X+Y= 15

So the sales of fruit C is 150 yuan.