2. Choose a point B on this side of the river to make AB perpendicular to the river, and AB is the width of the river.
3. Choose two points C and D by the river to make BC=CD.
4. Visually draw a straight line AC, which intersects the vertical line of BD at E,
5. The length of the measure is the width of the river.
Prove:
At △ABC and △EDC,
∠AB=∠EDC=90,
BC =DC,
∠ACB=∠ECD,
∴△ABC≌△EDC(ASA),
∴AB=DE.