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All Formulas of Math Application Problems in Grade Six
Number of copies × number of copies = total number of copies

Total copies/number of copies = number of copies

Total copies/number of copies = number of copies

1 multiple × multiple = multiple

Multiply1Multiply = Multiply

Multiply/Multiply = 1 Multiply

Speed × time = distance

Distance/speed = time

Distance/time = speed

Unit price × quantity = total price

Total price/unit price = quantity

Total price ÷ quantity = unit price

Work efficiency × working hours = total workload.

Total amount of work ÷ work efficiency = working hours

Total workload ÷ working time = working efficiency

Appendix+Appendix = Sum

And-one addend = another addend

Negative-negative = difference

Negative difference = negative

Difference+Minus = Minus

Factor × factor = product

Product ÷ One factor = another factor

Dividend = quotient

Dividend = divisor

Calculation formula of quotient × division = division of primary school mathematical graphics

Square c perimeter s area a side length perimeter = side length ×4 c=4a area = side length× side length s = a× a.

The surface area of a side of cube V volume = side length × side length× ×6 s Table =a×a×6 volume = side length× side length v=a×a×a 3 rectangle C perimeter S area A side length perimeter = (length+width )× 2 c = 2 (a+b) area = length× width s=ab 4 cuboid V volume S.×

Trapezoidal S area A upper bottom B lower bottom H height area = (upper bottom+lower bottom) × height ÷2 s=(a+b)× h÷2 8 circular S area C circumference ∏ d= diameter r= radius (1) circumference = diameter×∏ = 2×∏. Radius c=∏d=2∏r (2) area = radius× radius× 9 cylinder V volume H height S; Bottom area r bottom radius c bottom perimeter (1) lateral area = bottom perimeter × height (2) surface area = lateral area+bottom area× 2 (3) volume = bottom area× height (4) volume = lateral area ÷2× radius.

Cone v volume h height s; Base area r base radius volume = base area × height ÷3 total number ÷ total number = formula (sum+difference) ÷ 2 = large number (sum-difference) ÷ 2 = sum of decimal and multiple problems ÷ (multiple-1) = decimal × multiple = non-closed line of tree planting problem. Then the number of plants = number of nodes+1 = total length ÷ plant spacing-1 = total length × (number of plants-1) plant spacing = total length ÷ (number of plants -654438) then the number of plants = number of nodes = total length ÷. Then number of plants = number of segments-1 = total length ÷ plant spacing-1 total length = plant spacing × (number of plants+1) plant spacing = total length ÷ (number of plants+1) The quantitative relationship of tree planting problem on closed line is as follows: number of plants. ÷ Difference between two distributions = number of shares participating in distribution (big profit-small profit) ÷ Difference between two distributions = number of shares participating in distribution (big loss-small loss) ÷ Difference between two distributions = number of shares participating in distribution meets the requirements; Meeting distance = speed × meeting time = meeting distance; The sum of speed and speed = meeting distance; Meeting time; Catch up with the problem; Distance = catch up with time; Distance; Speed difference = catching distance; Catch up with time; Downstream speed = (downstream speed+countercurrent speed) ÷2 Water flow speed = (downstream speed-countercurrent speed) ÷2 Solute weight+solvent weight = solution weight ÷ solution weight × 100% = concentrated solution weight × concentration = solute weight ÷ concentration = solution weight profit and discount profit. × 100% increase or decrease = principal× increase or decrease percentage discount = actual selling price ÷ original selling price× 1 00% (discount <1) interest = principal× interest rate× time after tax interest = principal× interest rate× time × (1-)