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Elementary school mathematics exercises and tests Su Jiao Edition (Volume I) page 2 1 6, the first question, the second sub-item.
Xiaoming and Xiaohua each have a few dollars, and Xiaoming has more money than Xiaohua in 85 yuan. After they both went to 30 yuan, Xiaoming had twice as much money left as Xiaohua. How much money do they each have?

Solution: Let Xiaohua have one yuan, then Xiaoming has a +85 yuan.

According to the meaning of the question

(a-30)×2=a+85-30

2a-60=a+55

A= 1 15 yuan.

Xiao Mingyou 1 15+85=200 yuan.