Equations and equations in 1
2.( 1)× (2)× (3)× (4)√ (5)× (6)√
4.( 1)3x=270
(2)82.5 x = 17.5
(3)x+26=38
(4) 14-6+x=36
Properties of the second kind of equation and its solution (1)
4.x=60 x=3. 1
x=2.9 x=5 1
5.x+38=90 x+x=36
x=52 x= 18
The third lesson is the nature of equation and the practice of solving equation (1)
1.( 1)√ (2)× (3)√ (4)√
2.x = 4a = 7.4y = 14.3 x = 9. 1
4.75+x=60+60 19+x=48
x=45 x=29
The Properties of the Fourth Equation and the Solution of Equation (2)
3.x = 3 1x = 8. 1x = 2x = 12.8
5.( 1)5x = 85(2)3.2x = 12.8
x= 17 x=4
(3)4x= 17.2
x=4.3
The Nature of Equation and Solving Equation Lesson 5 (2) Exercise
2.x = 148 x = 958 x = 1. 1x = 7
3.( 1)√ (2)√ (3)√ (4)×?
4.88+x=2 10 1.4x=3.36
x= 122 x=2.4
In the sixth class, use equations to solve practical problems.
2.x= 12.7 x=0.9 x=64 x=30
5.( 1)3.6-x=2. 1
x= 1.5
(2) 16x= 12× 12
x=9
In the seventh class, we practice using equation (1) to solve practical problems.
3.( 1)46-x = 29(2) 1.5x = 15
x= 17 x= 10
In the eighth class, use equation (2) to solve practical problems
3.x=8 x= 1 1 x=6
4.640+30x= 1450
x=27
5. 1200- 1 18x = 138
x=9
6. 1/2( 13+ 17)x = 360
x=24
Lesson 9 Setting Equations to Solve Practical Problems (2) Exercises.
2.x= 12 x= 15 x=24
4.56×25+45x=3020
x=36
5.20x-60=20× 15
x= 18
10 time series equation to solve practical problems (3)
2.( 1)3x+2x=95 (2)24+3x=87
x= 19 x=2 1
5.4x-x=480
x= 160
6.2( 1.5x+x)= 100
x=20
Lesson 65438 Solving Practical Problems with Sequence Equation (3) Exercise
3.x=3 x=3 x= 1.8
4.3x+24=300
x=92
5.20× 15+ 12x=600
x=25
12 time series equation to solve practical problems (4)
3.(90-75)x=45
x=3
5.2(2 1+x)=72
x= 15
6.(77+65)x=568
x=4
In class 13, use equation (4) to solve practical problems.
5.3.6(x-60)= 18
x=65
6.5x-3x=6
x=3
Organize exercises in 14 class (1)
3.( 1)4x = 17.2(2)x+68 = 100
x=4.3 x=32
5x = 40
x=8
(4) 1.5x=45
x=30
45-30= 15
15 class arrangement and practice
4. 15x+4.5=49.5
x=3
5.2x+6=72 5y-7=48
x=33 y= 1 1
6.3x- 10=90-x
x=25
Synthesis and practice of 16 class
1.( 1) 176- 105=7 1
75-7 1 = 4 (kg)
He is 4 kilograms overweight.
(2) Omission
Autonomous detection (1)
Second, 1.×? 2.×? 3.×? 4.√?
5.×? 6.√? 7.√? 8.×?
Three. 1.42.23.34.25.①
6.① 7.③ 8.② 9.②
V.3. ( 1) X-524 = 156
x=680
(2)420-y=293
y= 127
4.( 1)x-50=85
x= 135
(2) 5 10 ÷ 85 = 6 (pieces)
Unit 2 statistical chart of broken lines
1 type simplex broken line statistical chart
2.( 1) Omit
(2) 15 ÷ 3 = 5 (ten thousand yuan)
(3) 8+ 10+ 15+22 = 55 (ten thousand yuan)
55 ÷ 14 = 13.75 (ten thousand yuan)
Lesson 2 Practice of Single Broken Line Statistical Diagram
2.( 1) Omit
(2) (240+230+245+255+260+270) ÷ 6 = 250 (name)
At the age of 3.2, he was slightly taller.
(1) has the most pulse beats, and 14 years old has the least pulse beats.
(2) The pulse rate varies greatly between 2 and 5 years old.
(3) About 10 years ago.
Statistical table of the third kind of composite broken line
1.( 1)5 (2)6 14 22
(3) 16.6
Step 3 sketch
(1) 65438+February sold the most color TVs,165438+1October sold the most refrigerators.
(2) The sales volume of color TV sets is on the rise, while the sales volume of refrigerators rises first and then falls.
Lesson 4 Practice of Composite Broken Line Statistical Diagram
1.( 1)20 12 is the closest.
(2) The number of ordinary greeting cards received is decreasing year by year, while the number of electronic greeting cards received is increasing year by year.
Lesson 6 Synthesis and Practice (2)
1.( 1) omitted.
(2) The growth rate of A tree is faster than that of B tree, and the number of A trees is higher than that of B trees.
(3) the eighth year
2.( 1) 10 (2)60 (3)80 85
Autonomous detection (2)
I. 1. ② 2.③ 3.③
Three. 2.( 1) Omit
(2)① 20
② 1 2 1 1
③ 125 146
3.( 1)5 (2)30 25 20 10 (3)23
4.( 1) Liang (2)20 1 1
5.( 1)5 2 5 6 (2)23 (3)5 6 (4) Omitted
Factor and multiple of the third unit
Multiples and factors of 1 class (1)
1. Multiple factors Multiple factors Multiple factors
7.2 12 3 8 4 6
1 2 3 4 6 8 12 24
The second kind of multiple sum factor (2)
3.3 6 12 18 2 1 27 30 36 42
7 14 2 1 28 35 42
2 1 42
4. 1 2 3 4 6 8 12 24
1 2 3 5 6 10 15 30
1 2 3 6
Characteristics of multiples of 2 and 5 in the third category
2.( 1)① (2)② (3)② (4)① (5)③ ③
Lesson 4 Characteristics of Multiples of 3
3.249 942 495 (the answer is not unique)
4.( 1)√ (2)√ (3)× (4)× (5)× (6)√ (7)× (8)√
The fifth lesson is a characteristic exercise of multiples of 2. , 3 and 5.
The circumference is 20cm, the length and width are prime numbers, the length is 7cm and the width is 3cm.
7× 3 = 2 1 (square centimeter)
6.3 and 8
Lesson 6 Prime Numbers and Composite Numbers
3.( 1)× (2)√ (3)× (4)× (5)√
4.( 1)③ (2)① (3)③ (4)③
Decomposition of the seventh kind of prime factor
5.2 19
The eighth common factor and the greatest common factor
4.( 1)6 cm
(2) Each ship can take up to 9 people and hire at least 5 ships.
(3) Plant at least 50 trees.
Lesson 9 Practice of Common Factor and Maximum Factor
4.( 1) The maximum length of each segment is 4m, and * * * is cut into 9 segments.
(2) The maximum side length is 9 cm, and a * * can be cut into a square like 12.
(3) Each team has at most 6 people, which can be divided into 13 teams.
There are 7 "three good students".
Common Multiples and Least Common Multiples in 10 Class
6. The minimum length of a square is12cm.
1 1 class common multiple and minimum common multiple exercises.
4.( 1)√ (2)√ (3)× (4)√
5.( 1) 7 am
(2) At least 56 students.
If the number of students is between 120 and 180, there are 168 students.
Comparison between the least common multiple and the greatest common factor in 12 class.
2.( 1)√ (2)√ (3)× (4)×
4.6 1
Organize exercises in 13 class (1)
2.( 1)② (2)② (3)②
3.( 1)× (2)× (3)× (4)√
14 class arrangement and practice (2)
2.( 1)√ (2)√ (3)× (4)√
4. There are at most 12 fruit bowls, each with 4 jellies and 3 chocolates.
15 lesson synthesis and exercise (1)
2.( 1)② (2)② (3)③ (4)③ (5)①
3. At least 324 yuan.
16 course synthesis and exercises (2)
3. Up to 7 people.
Independent detection (3)
Two. 1.√ 2.√ 3.√ 4.×
5.× 6.× 7.× 8.×
Three. 1.22.23.34.④
5.① 6.② 7.② 8.④
5.3. At least 36 cases.
4. The side length is at least 24 cm.
5. There are four rabbits at most. Each rabbit is 9 mushrooms and 8 radishes.
Unit 4 Significance and Properties of Fractions
Practice of Music Score Meaning in the Second Classroom
4. (1)1/4116 (2)116 (3) is omitted.
The relationship between third-class fraction and division
4. (1)1106 ÷10 = 3/5 (length)
(2) 1/8 4 ÷ 8 = 1/2 (m)
(3) 5 ÷ 7 = 5/7 (ton)
6 ÷ 10 = 3/5 (ton)
The first mill grinds 5/7 tons per hour, and the second mill grinds 3/5 tons per hour.
In the fourth category, one number is a fraction of another (1)?
3.( 1)2/5 5/ 14 1/7
(2) 10/ 13 12/ 13 1 1/ 10
In the fifth category, a fraction of one number is a fraction of another (2)
4.( 1)× (2)× (3)× (4)×
True and false scores of class 6
3.( 1)6/7、2/9、43/ 100、 1 14/ 1 15 3/3、5/4、9/2、2 13/7
(2) 1/5、2/5、3/5、4/5 5/ 1、5/2、5/3、5/4
(3) True110 3
(4)8 8/9 1/9
(5)< > < = > 9/8
The second group collected more on average.
Exchange of Fractions and Decimals of the Eighth Category (1)
4. (1) 0.9 = 9/109/10 > 3/4 fruit ring area is larger.
(3)0. 1 3/7 2 1/20
Lesson 9 Exchange of Fractions and Decimals (2)
4.4 ÷ 6 = 2/3 (flower) 3 ÷ 4 = 3/4 (flower) 6 ÷ 10 = 3/5 (flower)
3/4>2/3>3/5
Xiaomei is the fastest and Xiaolan is the slowest.
5.3× (1-1/5) =12/5 (m)
3- 1/5 = 14/5 (m)
12/5< 14/5
The rest of the second rope is very long.
Basic properties of 10 class fraction
7.10/1215/18 20/24 25/30 (the answer is not unique)
About 1 1 class hour (1)
3.( 1)③ (2)③ (3)③
About 12 class hours (2)
3.( 1)× (2)√ (3)√ (4)× (5)√
6.24/32
Pass 13 class.
4.( 1)× (2)× (3)√ (4)√
14 class performance comparison
4.> < = < > > < = 2/ 15
Mei Mei runs faster.
18 class arrangement and practice (3)
4. Enlarge the denominator of (1) by 4 times 16/20.
(2) Molecule divided by 8 2/3
Synthesis and Practice (1)
2.( 1) omit (2)4 (3) 10.
Lesson 20 Synthesis and Practice (2)
3.( 1) Wang Jun 1/2 (2)A
2 1 Course Synthesis and Practice (3)
1.( 1)54/8 1 162/243 468/729 1458/2 187
(2)4/8 2/4 1/2 0.5/ 1
(3)4/ 16 5/32 6/64 7/ 128
Independent detection (4)
Three. 1.32.43.34.25.④
6.④ 7.② 8.① 9.③ 10.④
Verb (abbreviation of verb) 1. 1/59/5m
3.8/ 15 8÷(8+ 15)=8/23
5.45 ÷ 5 = 9 (kg)
3 ÷ 5 = 3/5 (box)
Mid-term autonomous detection (1)
Three. 1.22.33.34.35.36.37.28.①
Six, 3.4 ÷ 3 = 4/3 (kg)
3 ÷ 4 = 3/4 (kg)
4. Zhou Hao: 8/ 10
Zhao Hua: 6/8
Wu Shuo: 7/9
8/ 10 > 7/9 > 6/8, Zhou Hao's correct rate is higher.
Mid-term autonomous detection (2)
Three. 1.32.33.44.25. 16.27.③
6, 2. 100 ÷ 42 = 50/2 1 (kg)
42 ÷ 100 = 2 1/50 (kg)
4.12cm
5. Zhang Peng: 6/ 10 = 3/5.
Li Jun: 15/25 = 3/5
Wang Qiang: 14/20 = 7/ 10.
Wang Qiang throws more accurately.
Unit 5 Fractional addition and subtraction
1 Addition and subtraction of fractions with different denominators (1)
5.( 1) 1/6+ 1/4=5/ 12
(2) 8/ 15+5/6 = 4 1/30 (ton)
5/6-8/ 15 = 3/ 10 (ton)
Addition and subtraction of fractions with different denominators of the second kind (2)
3. (1) 2/3+5/4 = 23/12 (km)
5/4-2/3 = 7/ 12 (km)
3/2-5/4 = 1/4 (km)
(2)① 1/3+3/8= 17/24
②3/8- 1/6=5/24
The third kind of mixed operation of addition and subtraction of fractions with different denominators (1)
3. (1)1/2-1/5-1/6 = 2/15 (ton)
(2) 1- 1/5- 1/6= 1930
(3) 1- 1/2-3/8= 1/8
(4)5/8+3/5- 1=9/40
Lesson 4 Addition and subtraction of fractions with different denominators (2)
4.( 1) 3/4- 1/8 = 5/8 (km)
3/4+5/8 = 1 1/8 (km)
(2)3/8+3/8=3/4
1-3/4= 1/4
(3) 2/5+3/8+110 = 7/8 (ton)
The fifth class is completed and practiced
4.( 1)3/5+3/5=6/5 6/5- 1= 1/5
Overproduction, overproduction 1/5.
(2) 1 1-( 12/5+ 12/5+3/ 10)= 59/ 10(m)
The sixth class is synthesis and exercise
5. 1/6+ 1/3+ 1/2= 1
Xiaohong drinks as much milk as water.
Autonomous detection (5)
Two. 1.×2.×3.× 4.×
5.×6.√
Four. 1.7/10-1/5-3/10 =1/5 (m)
4.5/8+5/8-1/6 =13/12 (kg)
Unit 6 circle
Understand the circle in lesson 1 (1)
4.( 1 )× (2)√ (3)× (4) √
The second lesson on the understanding of the circle (2)
1.( 1)√ (2)× (3)√ (4) √ (5) √
Know the fan in the third lesson
3.( 1)× (2) √ (3)× (4) √ (5) √
Circumference of the fourth kind of circle (1)
3.( 1)× (2)× (3)√ (4)× (5)×
Lesson 5 Circumference (2)
4. (1) (3.14× 40+60× 2 )× 5 =1228 (m)
(2) 47.1÷10 ÷ 3.14 =1.5 (m)
Lesson 6 Circumference (3)
2.( 1)× (2)√ (3)× (4)×
3.( 1)② (2)①
The area of the seventh circle (1)
4.( 1)√ (2)× (3)√ (4)√
5. (1) 3.14× (30 ÷ 2) 2 = 706.5 (square meter)
(2) The maximum circle has a diameter of 4m and a radius of 2m.
5× 4-(3. 14× 22) = 7.44 (square meter)
Area of the Eighth Circle (2)
3.( 1)③ (2)① (3)②
4. (2) 3.14× (6+1) 2-3.14× 62 = 40.82 (square meter)
Lesson 9 Area of Circle (3)
3.3.14×102 = 314 (m2)
5.( 1) circumference: 3.14× 6+10× 38.84m.
Area:10× 6 = 60m2.
(2) 3.14× 42×1/2-3.14× 22 =12.56 (square decimeter)
Organize exercises in class 10 (1)
3.( 1)× (2)√ (3)√ (4)√ (5)×
4.( 1) circumference: 3.14× 6× 2 = 37.68cm.
Area: 3.14× 62 =113.04 (square centimeter)
1 1 classroom arrangement and practice (2)
3. (1) 3.14× (20+2) = 69.08 (m)
(2) 47.1÷ 3.14 =15 (m)
3.14× (15/2) 2 =176.625 (m2)
(3)94.2÷3. 14 = 30 (m)
3. 14× (30 ÷ 2) 2 = 706.5 (m2)
706.5× 15 = 10597.5 (g)
12 class arrangement and practice (3)
3.188.4 ÷ 600 ÷ 3.14 = 0.1(m)
5. (1) 3.14× 2.8 = 8.792 (m)
8.792