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Mathematics [geometry] in the first grade of junior high school
Solution:

OE division ∠BOC

Prove:

∫∠AOB is a right angle.

∴∠AOB=90

∫∠BOC = 50

∴∠AOC=∠AOB-∠BOC=90-50=40

∫OD splitting∠ ∠AOC

∴∠COD=∠AOC/2=40/2=20

∫∠DOE = 45

∴∠EOC=∠DOE-∠COD=45-20=25

∴∠BOE=∠BOC-∠EOC=50-25=25

∴∠BOE=∠EOC

OE Split Bank of China

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