There are three people, A, B and C. A is 3 years older than B and B is 2 years younger than C. The sum of the three people's ages is 109. Find out the ages of A, B and C respectively.

Answer:

Solution 1: If A subtracts 3 and C subtracts 1, A is twice as much as B, C is 1/2 of B. Then the remaining age of109-1-3 =105 is 2+1+12 = 7/2 of B. The above results show that B is/.

Solution 2: According to the meaning of the question, A = B× 2+3 and B = C× 2-2, then A = [(C× 2-2) ]× 2+3 = C× 4- 1, and the sum of the three ages is (c× 4-1). Then A = 16×4- 1=63 years old, and B = 16×2-2=30 years old.

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