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A problem in section 5.3 (Multiplication of Polynomials) of seventh grade mathematics exercise book of Zhejiang Education Press.
Ha ha! !
These four numbers can be n n+ 1 n+2 n+3 in turn.
(n+2)(n+3)=n^2+5n+6
n(n+ 1)=n^2+n
So their difference is 4n+6.
As long as you know the difference between them, you can get n by subtracting 6 and dividing by 4! ! ! ! ! ! ! ! ! !