I don't quite understand the meaning of the second question, so I only did the first question of the first and second questions.

First question

f(m- 1)+f(2m- 1)>0

f(m- 1)>-f(2m- 1)

Because it is an odd function.

f(m- 1)>f(-2m+ 1)

Reduce in the world

So it is a monotone decreasing function on the domain.

m- 1 & lt； -2m+ 1

m & lt2/3

Its domain (-2,2) should be considered.

So the answer is (0,2/3).

The deformation problem is basically the same as the above idea.

the second question

( 1)

Let x=-y

f(x+y)=f(x)+f(y)

f(0)=f(x)+f(-x)

Let x=y=0.

f(0)=f(0)+f(0)

f(0)=0

f(x)+

f(-x)=0

f(x)=-

f(-x)

So it's odd function.

(it says x in it.

y

Belongs to any real number and can be set at will)

(2) The idea should still be to use the formula f(x+y)=f(x)+f(y) to deform and then compare the sizes with its actual function.

The thinking of the above questions should be correct, but the calculation may not be correct. It's best to follow the train of thought and calculate it yourself to deepen your impression.