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How to calculate the total increment of a series of numbers?
LZ, what are you doing? . . This is not the sum of high school arithmetic progression. ...

The growth of the series is arithmetic progression (that is, the series with equal growth), then the series is a quadratic function; If the increase of the series is arithmetic progression, then the series is a cubic function ... and so on. This is the knowledge of series.

As for this question,

5-2=3

10-5=5

17- 10=7

……

an-a(n- 1)=2n- 1

Ann (No.N)

These formulas add up left and right.

Available an-2 = 3+5+7+...+2n- 1.

Note T = 3+5+7+...+2n- 1. Obviously, t is the total increment.

By the way, let me tell you about Gaussian algorithm. After all, this topic should not be in junior high school.

3+5+7+...+2n- 1

2n- 1+2n-3+2n-5+...+3 (reverse writing)

Then add the items, and the corresponding sum of each item is the same number 3+2n- 1, which is the sum of the first item and the last item.

Then 2T=(3+2n- 1)(n- 1).

N- 1 is the total number of terms of t.

So the total increase is t = [3+(2n-1) ]× (n-1) ÷ 2, which is how it came about. . .