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Mathematical function test questions for senior high school entrance examination
If DF and CE intersect at M(x 1, y 1), then F (x 1, 0), D(x 1, k/x 1), E (0, y/kloc-0)

The area of the triangle DME is | em || MD |

/2 = x 1(| y 1 |+k/x 1)

/2,

The area of the triangle CMF is | FM || MC |

/2 = | y 1 |(x 1+k/| y 1 |)

/2

Obviously equal, so the areas of △CEF and △DEF are equal.

The slope of the straight line EF is -y 1/x 1, and the slope of the straight line CD is (k/x1-y1)/(x1-k/y1) =-y/.

The straight line EF is parallel to the straight line CD,

So △AOB is similar to △FOE.