Solve math problems and find the master key that can open four locks.
The answer is 247. You can do this. You set the hundred digits as A, the ten digits as B and the single digits as C. Then, from the meaning in the question, we can know that B = 2A and C = A+5. The first condition c must be radix, so a must be even. A # 0, a, b and c are all natural numbers greater than 1 less than 9. C=a+5.a may be 2 or 4. If a=2, then 2+4+7= 13 is a prime number, and a=4, 4+8+9=2 1 is not a prime number, so a can only be 2, so you can calculate it yourself!