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Answers from top students in grade six
Simple equation:

1, with a total length of one meter.

2. Then Team A built a× 2/5-24m.

3. The first-stage repair of Team B (A× 2/5-24) ÷ 8× 3m.

4. The equation is listed as follows: according to the total length, the number of meters repaired by Party A is subtracted, and then the number of meters repaired by Party B in the first stage is equal to 132 meters.

a-(a×2/5-24)-(a×2/5-24)÷8×3 = 132

Solve a=220 (m)