The reaction rate is directly proportional to the square of a and inversely proportional to B.

B has increased 100%. How did the proportion of A change?

Let the rate x be proportional to the square of a and inversely proportional to b.

X = k (the square of a /b) K is a setting coefficient and can be ignored.

B becomes 2B. A How can I change to keep the speed constant? Then the following equation is obtained.

X 1=K (a square /B) X2=K (a new square /2b)

If the rate is constant, then the new square of X 1=X2, a is twice the square.

Then the new A= A has twice the root sign.

The radical number 2= 1.4, so the new a =1.4a.

This is an increase of 40%