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Complex problems in children's mathematics
7 points against 3 points wrong 2, 3 points against 2 points wrong 3, 1 1 points against 4 points wrong.

Because the answers to A are all "+",and then look at A and E, suppose that the correct answer to question 1 is "+",that is, the first question of E is wrong, and everything else is wrong. Questions 3, 4 and 6 of A are wrong, which contradicts the 7-phase of A, so the first question of E is correct, that is, the correct answer to the first question is "-". Similarly, the correct answer to the second question is "+"

If e and F F are wrong in the second question, he can only be wrong again. Suppose the third question is wrong, his answers to other questions are correct, and the third and fourth questions of E are also wrong, so the answer to the third question of F is correct, that is, the correct answer to the third question is "-"

According to the correct answers to 1, 2, 3, we can know that 1, 2, 3 of D are all wrong, so the answers to 5 and 6 of D are all right, that is, the correct answer to the fifth question is "+"and the correct answer to the sixth question is "-"

The answers to questions 3 and 6 of A are wrong, and the answer to question 4 is definitely right, so the correct answer to question 4 is "+".

The correct answer should be 1-2+3-4+5+6-.

So the score of F for 4 and 2 is 10.