Solution: Suppose the point of sale buys X every day,
Obviously, when X ∈ [250 250,400], the monthly profit can be maximized.
So the monthly profit y is
y=20? 6? 10.50x+ 10? 6? 10.50? 6? 1250+ 10? 6? 10.08(x-250)-30? 6? 10.35x
=0.3x+ 1050,x∈[250,400]。
Because the function y is the increasing function in [250,400],
Therefore, when x=400, the maximum value of y is 1 170 yuan.
Answer: Buying 400 points every day can maximize the monthly profit, which means that he can earn at most 1 170 yuan a month.
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