If a43 is a multiple of 45, there is (1000a+430+b)/45 = 22a+9+(10a+25+b)/45. A meets the above conditions.

When b=0, the number 2 in 0~9 satisfies the condition of a.

When b=5, the number 6 satisfies the condition of a.

This number may be 2430 or 6435.