1m = 1m

80km/h = 200/9m/s =v=at

(ds)^2/dt^2=a ①

dv/dt=-a ②

Integrate both sides of Formula ①:

ds/dt=at+C 1

s= 1/2at^2+C 1t+C2

To integrate both sides of Equation ②:

At +C3

Substitute s=0, t=0 and v=200/9 into ① ② to get C 1=0.

C2=0 C3=200/9

Namely:

260= 1/2at^2

200/9=at

Simultaneous solution: a= 1000/ 1053=0.95.

Answer: It takes 0.95m/s acceleration in the opposite direction within 260 meters to stop the motorcycle.