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A math problem: shops usually use the following methods to determine the price of assorted sweets made of two kinds of sweets. ...
Shops usually use the following methods to determine the price of mixing two kinds of candy. Let the unit price of candy A be C yuan/kg, and the price list of candy B be D yuan/kg. Then the unit price of candy mixed with candy A and candy B is mc+md/m+n yuan /kg. At present, two kinds of mixed sugars A and B are made by mixing two kinds of sugars with different unit prices. Among them, the mixed sugar A consists of 10 Jin A sugar and 10 Jin B sugar, and the mixed sugar B consists of 100 Yuan A sugar and 100 Yuan B sugar. What kind of mixed sugar do you think has a higher unit price? Why?

Solution, get:

The unit price of methyl sugar is (10a+10b)/20 = (a+b)/2.

The unit price of ethyl sugar is (100+100)/(100/a+100/b) = 2ab/(a+b).

Assuming that the unit price of A is not greater than B, there are:

(a+b)/2 & lt; =2ab/(a+b) because a, b >;; 0

So: (a+b) 2

a^2+2ab+b^2<; =4ab

a^2-2ab+b^2<; =0

(a+b)^2<; =0

The square of any number is not less than 0, and a, b >;; 0

So the above formula should be greater than 0, so the assumption is not valid.

The conclusion is that the unit price of A is greater than that of B.

A:A's unit price is relatively high.