Because e and f are neutral lines, EF//BG
∴ ∠G=∠GBC
∫BQ split ∠PBC
∴ ∠G=∠PBG
∴ BP=PG
∫CQ = 1/3EC
∴CQ:EQ= 1:2
Here we go again ∵ EF//BC
∴ CQ:EQ=BC:EG= 1:2
∴EG= 12
That is, EP+BP= 12.
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