I saw a math problem in the first grade of primary school today and found it very interesting. I don't know the standard answer. Welcome men who are IQ students in the first grade of primary school like me.

or

Woman to answer, haha, my idea is:

1. First, make rules. Through the research on the laws of figures and numbers, the assumed laws are as follows:

(1). If two nested graphs are not connected, add the values of the two graphs.

(2) If two nested graphs are connected, only the value of the external graph is calculated.

2. According to the number corresponding to the above figure:

According to the laws of the above graphs, two groups of graphs have an equation.

(1). If the circles of a square don't want to be connected, it corresponds to 3; The connection of circles and squares corresponds to 1.

The round box is 1.

Apply the rules I made above:

Square+circle =3

Circle = 1

So, box =2.

(2) If the triangles of the box set are not connected, it corresponds to 6, and if the triangles of the triangle set are connected, it corresponds to 4.

Square+triangle =6

Triangle =4

So, box =2.

Because the square values obtained by (1) and (2) are both 2, it proves that the law I assume is applicable to the laws of figures and numbers.

(3) The circles of a triangle are not connected.

By (1) and (2), we get triangle =4 and circle = 1.

Suppose the law is reasonable.

Therefore, according to the law, the corresponding number of disjoint triangles is: triangle+circle =4+ 1=5.