The condition 1, taken alone, is definitely invalid, x 2.

Let's look at condition 2,

Condition 2, alone, is definitely not true, because √ x > 0, but x

Since the two conditions are not established separately, consider joining.

x^2<； y，√x & lt； Y must be a non-negative number, so Y must be a positive number greater than 0, so the conclusion is not sufficient. You can also give a counterexample, assuming that X = 4, Y = 17 and X 2 = 16.

So even if two conditions exist at the same time, x>y's conclusion is sufficient, so choose E.