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Mathematical mural problems:
Suppose: the wall area to be painted in each room is X.

Then it is (8x-50)/3-10 = (10x+40)/5.

10X=520

X=52

A: The wall area to be painted in each room is 52㎡.

Analysis: The equation is based on "each first-class mechanic paints more walls 10㎡ a day than the second-class mechanic".

Namely: painting area of first-class mechanic-10= painting area of second-class mechanic.