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Nantong mathematics Moore
A, the final electron is in equilibrium under the action of electric field force and Lorentz force. Let the length, width and height of Hall element be A, B and C respectively, where qUc=qvB, and the microscopic expression of current is I=nqvS=nqvbc, so the larger U = BinqB. B, the greater the potential difference between the upper and lower surfaces. Therefore, a.

The greater the values of b and k, the greater the variation of b with z according to the magnetic induction intensity B=B0+kz, and the greater the variation of u with z according to U = BINQB, that is, the higher the sensitivity of the sensor (△U△z), so b is correct.

C. free electrons move in the hall element. According to the left-handed rule, electrons are biased towards the lower surface, so the upper surface potential is high. So, C is wrong.

So choose ab.