The possibility of 30 people randomly choosing 3 people is: C30(3) = P30(3)/3! = (30*29*28)/6 = 5*29*28

The probability that A and B are drawn at the same time is C28 (1) ÷ C30 (3) = 28 ÷ (5 * 29 * 28) =1/(5 * 29).

So the probability of being drawn at different times =1-1/(5 * 29) = 99.3%.