1234567890*47=58024690830

It seems that no one can answer you.

Let me try. If I am wrong, don't blame me.

Never mind 1234567890, 0. Say first 123456789. All the same.

Before saying 123456789, let's say 123456790.

One feature is 123456790. Multiply by a multiple other than 3, and there will be a "missing number".

take for example

123456790 *10 =1234567900 (missing 8)

123456790 *11=1358024690 (missing 7)

123456790 *13 =1604938270 (missing 5)

123456790 *14 =1728395060 (missing 4)

123456790 *16 =1975308640 (missing 2)

1 23456790 *17 = 2098765430 (missing1)

Try other numbers yourself, similar to the ones above.

Moreover, the number of omissions plus the multiplier is equal to a multiple of 9.

Then123456789 =123456790-1.

therefore

123456789 * a =( 123456790- 1)* a

= 123456790a-a

Obviously, the previous number is "missing number". If you subtract a two-digit number, it will affect hundreds at most.

This first ensures that every number above 1000 digits is different, so that all numbers from 0 to 9 are 7.

We notice that the last digit of 12345679 is 9.

but

9* 1=9 9*2= 18 9*3 =27 9*4=36 9*5=45 9*6=54 9*7=63 9*8=72 9*9=8 1

So the unit of multiplier plus product is 10.

This ensures that

"missing number" -a

After that, bad cell = missing ten (why)

So there was this. From 0 to 9, nine times out of ten.

Moreover, because the multiplier A is relatively small within 50, it is difficult to affect the hundred digits, so the number from 0 to 90 is likely to be 9.

The missing one is the missing number. It turns out that this number always appears in ten places, because only ten places can be left for it, but why don't I care every time? Think for yourself.