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Ancient mathematical problems
1. Today, someone * * * bought chicken, and they offered nine, making eleven, and they offered six, less than sixteen. Ask the number of people, chicken geometry?

Answer:

Let the number of chickens be x and the cost be y, then

9x- 1 1=y

6x+ 16=y

The solution is x=9 y=70.

2. If you don't know the depth of a well, first fold the rope 3 into the well, the rope outside the well is four feet long, and then fold the rope 4 into the well, and the rope outside the well is one foot long. Q: What are the geometries of well depth and rope length?

Answer:

Well depth x

Rope length y

x+4=y/3

x+ 1=y/4

x=8

y=36

This well is 8 feet deep.

This rope is 36 feet long.

There are some things today, but I don't know their quantity. The number of three plus three is two plus five, and the number of three plus seven is two. What is the geometry of things?

Answer: The remainder 2 is divided by 3 times the common multiple of 5 and 7, and the remainder 1 is divided by 70 to get 140.

Divide the remainder 3 by 5 times the common multiple of 3 and 7, and divide the remainder 1 by 2 1 to get 63.

The remainder 2 is divided by 7 times the common multiple of 5 and 3, and the remainder 1 is divided by 15 to get 30.

Three numbers add up to 233, plus or minus an integer multiple of 105.

This is a special case of the legendary China remainder theorem. ...

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