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Math problems in the sixth grade of primary school
There are three kinds of balls *** 160. If one third of the red ball, one quarter of the yellow ball and one fifth of the white ball are removed, there are still 120 balls left. If one fifth of the red ball, one quarter of the yellow ball and one third of the white ball are removed, 1 16 is left. How many yellow balls, red balls and white balls are there?

Solution, get:

1/3- 1/5=2/ 15

215 of the white ball is greater than 215 of the red ball; 120- 1 16=4.

The number of white balls is 4÷2/ 15=30.

If all three balls are taken out 1/4, there is still160× (1-1/4) =120.

It shows that1/3-1/4 =1/2 of the red ball is equal to1/4-1/5 =1/20 of the white ball.

The ratio of red to white is1/20:112 = 3: 5.

Red: 30(5-3)×3 = 45

White: 45÷3×5=75

Huang: 160-45-75=40.