( 1? Proof: in △ACB and △ECD? ∠∠ACB =∠ECD =？ 90 degrees

∴∠ 1+∠ECB=∠2+∠ECB？

∴∠ 1=∠2

AC = CE = CB = CD，

∴∠A=∠D=45 degrees?

∴△ACB≌△ECD？

∴CF=CH

(2? A:? The quadrilateral ACDM is a diamond.

Proof: ∫∠ACB =∠ECD =? 90 degrees, ∠BCE= 45 degrees

∴∠∠ 1 = 45 degrees? 2 = 45 degrees?

∵∠E=45 degrees ∠B=45 degrees? ,

∴∠ 1=∠E？ ∠2=∠B

∴AC∥MD,CD∥AM？ ,? ∴ACDM is a parallelogram.

AC = CD again? ∴ACDM is a diamond.