According to sine theorem:

sinC=√3sinAsinC-sinCcosA

1 =√3 sine curve

1/2=(√3/2) Sina -( 1/2)cosA

1/2=sin(A-π/6)

A-π/6=π/6

A=π/3

(2)

a=2，

According to cosine theorem:

2^2=b^2+c^2-2bc*cos(π/3)

4=b^2+c^2-bc

( 1/2)bc*sin(π/3)=√3

( 1/2)bc(√3/2)=√3

bc=4.......................①

4=(b+c)^2-3bc

4=(b+c)^2- 12

(b+c)^2= 16

b+c=4..................②

From ① ②: B and C are equations.

Two x 2-4x+4 = 0

(x-2)^2=0

b=c=2