Obviously, this topic has a * * * property, which is divided by n (n- 1). If you add 1 to this number, the problem is found. This number plus 1 becomes a multiple of 10, 9, ... 2. Therefore, the smallest N+ 1 is the least common multiple of 2, 3, 4 ... and 10. That is n+1= 2 * 3 * 3 * 4 * 5 * 7 = 280 * 9 = 2520.

So the minimum value of n is 25 19.