Then you really have a problem with this topic! !

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Solve the problem:

The number of students in class A is X, and the number of students in class B is Y. 。

① 1/2x+3/5y=58

x+y= 105

② Both sides of the first equation are multiplied by10: 5x+6y = 580Ⅰ.

Both sides of the second equation are multiplied by 5: 5x+5y = 525 Ⅱ.

ⅰ-ⅱ:y = 55

Substitute into the second equation: x+55= 105.

x= 105-55

=50

A: There are 50 students in Class A and 55 students in Class B. ..