The answer is D.
Yi Zheng AE//BC, AB//ED
Expand ED to BC to F.
Angle BFD= angle ADF= angle EDC
DF=DC
BF=AD=DE
So the triangle BFD is equal to EDC.
Corner CED= corner CBD
Therefore, angle ADB= angle CBD+ angle ACB= angle CED+ angle AED= angle AEC.
Complete the certificate.