y=ax^2-3
Let the shot put coordinate be (x 1, 1.6) and the placement point be (x2,0), then
x2-x 1= 10 ( 1)
And (x 1, 1.6) and (x2, 0) are all on the parabola, then
1.6=a*x 1^2-3 (2)
0=a*x2^2-3 (3)
A, x 1, x2 can be solved by connecting three equations.