So the analytical formula of this linear function is y=-2x+7.

2. When the straight line y=4x-3 and y=0, x=3/4, so the point intersecting the X axis is (3/4,0).

The slope k=(0+3)/(3/4-3)=-4/3, so: y=-4x/3+b Replace (3, -3) with: b= 1,

So the analytical formula of this linear function is y=-4x/3+ 1.

3. The intersection of Y =1/2x+3 and Y axis is, and when x=0, y=3, so the intersection is (0,3).

The slope k=(- 1-3)/(2-0)=-2, so: y=-2x+b is replaced by (0,3): b=3.

So the analytical formula of this linear function is y=-2x+3.

or

I'll show you the way.

1. Let Y=aX+b and bring in (-4, 15) and (6,5) to calculate A and B.

2. Let the intersection point on the X axis be (x, 0) and bring it into the straight line y=4x-3, so this point (3/4, 0) brings (3/4, 0) and (3, -3) into y = ax+b..

3. If the point B(0, y) is brought into y= 1/2x+3, then B(0, 3) is brought into the linear function y = kx+b.