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What are the fixed points of the fixed-point problem y = k (x-2)+ 1 and y = k (x-4) in senior high school mathematics?
For the linear equation y=k(x-a)+b

Has nothing to do with k, that is, the coefficient of K =0.

x-a=0

y=b

(a, b) is the passing point.

The fixed point of y = k (x-2)+ 1 is (2, 1).

The fixed point of y = k (x-4) is (4,0).

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