If you haven't studied indefinite equations, you can use this idea.
Because 48 is a multiple of 6 (of course, 48 can also be a multiple of 4)
Therefore, the first choice is 6 m 8 and 4 m 0.
(Consider that the least common multiple of 4 and 6 is 12, that is, every two 6m can be replaced by three 4m. )
The second choice is to choose 6 from 6 meters and 3 from 4 meters.
The third option is 6.4 meters and 4.6 meters.
The fourth option is six meters for two and four meters for nine.
The fifth selection method is 0 for 6m and 12 for 4m.