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Mathematical function problems in grade three
Solution (1): let the resolution function of y and x be y=kx+b, let X = 20 and Y x=20, y = 360X=25, y=2 10 substitute y=kx+b to get the equations about k and b:

20k+b=360

25k+b=2 10

Solve the equation, k=-30 and b=960.

Therefore, y=-30x+960.

(2): As mentioned above, the profit of each kite is (x- 16) yuan, and the monthly sales volume is (-30x+960). The monthly profit is:

(x- 16)(-30x+960)

=-30x? +960x+480x- 15360

=-30x? + 1440x- 15360

=-30(x? -48x)- 15360

=-30(x? -48x+24? )- 15360+30×24?

=-30(x-24)? + 1920

When x=24, there is a maximum monthly profit, and the maximum monthly profit is 1920 yuan.

When each Facebook kite is priced as 24 yuan, it can get the maximum profit every month, and the maximum profit every month is 1920 yuan.